x^2+0.0014x+-0.0000722400=0

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Solution for x^2+0.0014x+-0.0000722400=0 equation: 



x^2+0.0014x+-0.0000722400=0

We add all the numbers together, and all the variables

x^2+0.0014x=0

a = 1; b = 0.0014; c = 0;
Δ = b2-4ac
Δ = 0.00142-4·1·0
Δ = 1.96E-6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0014)-\sqrt{1.96E-6}}{2*1}=\frac{-0.0014-\sqrt{1.96E-6}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0014)+\sqrt{1.96E-6}}{2*1}=\frac{-0.0014+\sqrt{1.96E-6}}{2}
$

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